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x^2+2.5x+2.5x+6.25=9
We move all terms to the left:
x^2+2.5x+2.5x+6.25-(9)=0
We add all the numbers together, and all the variables
x^2+5x-2.75=0
a = 1; b = 5; c = -2.75;
Δ = b2-4ac
Δ = 52-4·1·(-2.75)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-6}{2*1}=\frac{-11}{2} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+6}{2*1}=\frac{1}{2} =1/2 $
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